The probability for the scheduled flight in that the departs in the time is P(D) = 0.83, there are the probability that arrives on the time in P(A) = 0.82; there is also the probability that depart and arrives is P(D∩A) = 0.78. Determine the probability for the plane that arrives on time that gives the departed on the time? Determine also the time on departed given in the arrived time?

Solution:

A.) The probability will arrive on time that can given in departed on time

                        P(A/D) = P(D ∩ A) =  0.78    = 0.94

                                            P(D)        0.83

B.) The probability that the departed plane on the time that be given and arrived on time will be

                        P(D/A) = P (D ∩ A)  = 0.78   = 0.95

                                             P(A)        0.82


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